... Pour des orbites circulaires autour de la terre, nous venons de trouver . ... La distance d'un satellite au centre de la terre en m?tres est un nombre incommod?ment grand, m?me avant d'?tre port? ? ... Nous pouvons par contre multiplier l'expression de droite par (R E 3 / R E 3 ) = 1 et r?arranger alors les termes : . ... SQRT (25 638 838) = 5063.5 . ... C'est la forme pratique de la 3?me loi de Kepler pour les satellites de la terre. ... Prochaine ?tape: #22 Les cadres des r?f?rences : Les Bases . ...

For circular orbits around Earth, we found . ... The distance of a satellite from the center of Earth in meters is an inconveniently big number, even before we raise it to the 3rd power. ... SQRT (25 638 838) = 5063.5 From this . ... T= 5063.5 seconds SQRT(r') 3 = 5063 sec r'SQRT=(r') . This is the practical form of Kepler's 3rd law for Earth satellites. ... International communication satellites are in the equatorial plane of the Earth and have orbits with a 24-hour period. ...

Atlas . Saturn XV - 1980S28 . Atlas, the second of Saturn's known satellites, orbits near the outer edge of the A-ring and is about 40 by 20 kilometers (25 by 15 miles) in size. It is probably a shepherd satellite for Saturn's A-ring. Atlas was discovered by R. Terrile in 1980 from photographs taken by Voyager during its encounter with Saturn. Atlas Statistics . ... Mean density (gm/cm^3) . ... Rotational period (days) . Orbital period (days) . ... Credit: Calvin J. Hamilton) . ...