... Cleo batch system is purposed to control parallel tasks on computer clusters. It controls one or more task queues. tasks sceduling (all MPI implemetations are supported, most other parallel environments are supported too) . ... controllable user limits (max used cpus, task work time, etc.) . ... Any task in main will be queued to daughter queues if there aren't enough free own cpus (not shared with daughters). When daughter queues will get enough cpus for this task, it will be runned in main . ...
APPLIED PHYSICS LETTERS 87, 241110 2005 Second- and third-harmonic generation in birefringent photonic crystals and microcavities based on anisotropic porous silicon I. V. Soboleva,a E. M. Murchikova, A. A. Fedyanin,b and O. A. Aktsipetrov Department of Physics, M. V. Lomonosov Moscow State University, 119992 Moscow, Russia Received 14 June 2005 ; accepted 22 September 2005 ; published online 6 December 2005 One-dimensional anisotropic photonic ... 2005 American Institute of Physics. ...
... In the 1970s, George Ritzer transformed Kuhnian paradigm into a consolidativeimaginary paradigm and suggested multi-paradigmatic model of sociology. ... N.Y., 1972; Levine D. Visions of the sociological theory. ... 4 Kuhn T. The structure of scientific revolutions. ... 6 Ritzer G. Sociology: a multiple paradigm science. ... Cambridge, 1970. ... On theoretical sociology" (N.Y., 1957) "Paradigms: codification of sociological theory" "On social structure and science" (Chicago, 1996), "" "" "". . ...
The beamer class Manual for version 3.06. \begin{frame} \frametitle{There Is No Largest Prime Number} \framesubtitle{The proof uses \textit{reductio ad absurdum}.} \begin{theorem} There is no largest prime number. \end{theorem} \begin{proof} \begin{enumerate} \item<1-| alert@1> Suppose $p$ were the largest prime number. \item<2-> Let $q$ be the product of the first $p$ numbers. \item<3-> Then $q+1$ is not divisible by any of them. \item<1-> Thus $q+1$ is also prime and greater than $p$.\qedhere
... 0P ( E) , .. [7]: 0p ( E) = 2.72 max E-U min E-U min exp U -U U max -U min max min (21) Umax , (max) p. jp Uminjp , Umaxjp maxjp : 11 0p ( E) = 2.72 E-U max jp min jp min jp U max -U E-U min exp U max jp -U jp min jp (22) ( ) [6]: (23) pj(E)E =jp(E+Ujp)( E+Ujp), , U0p = Up0 = Umin : p 0(E)=2.72 max E+U min exp U U max -U min E max -U minpj min , (24) , Ujp = Upj = U : pj ( E) = 2.72 E+U max jp min jp min jp E -U , U max jp -U exp U (25) max jp min jp max Umax, (21 25), [4,8], , .. ... Nemin . ...