... Pour des orbites circulaires autour de la terre, nous venons de trouver . ... La distance d'un satellite au centre de la terre en m?tres est un nombre incommod?ment grand, m?me avant d'?tre port? ? ... Nous pouvons par contre multiplier l'expression de droite par (R E 3 / R E 3 ) = 1 et r?arranger alors les termes : . ... SQRT (25 638 838) = 5063.5 . ... C'est la forme pratique de la 3?me loi de Kepler pour les satellites de la terre. ... Prochaine ?tape: #22 Les cadres des r?f?rences : Les Bases . ...

For circular orbits around Earth, we found . ... The distance of a satellite from the center of Earth in meters is an inconveniently big number, even before we raise it to the 3rd power. ... SQRT (25 638 838) = 5063.5 From this . ... T= 5063.5 seconds SQRT(r') 3 = 5063 sec r'SQRT=(r') . This is the practical form of Kepler's 3rd law for Earth satellites. ... International communication satellites are in the equatorial plane of the Earth and have orbits with a 24-hour period. ...

Outer Natural Satellites Orbits Ephemerides. ... Choose type of the ephemeride: . ... Values of the orbital elements [ output e sin( ), e cos( ), sin(i) sin( ), sin(i) cos( ) ] . Distances between the osculating orbits . ... Choose Second Satellite (for the distances) U17 - Sycorax U18 - Prospero U19 - Setebos U20 - Stephano U21 - Trinculo U22 - Francisco U23 - Margaret U24 - Ferdinand . ... Enter initial date (years) . Enter final date (years) . ... Enter upper limit of frequency deg/year . ...

... The first time you acquire an object you must include the overhead for the guide star acquisition. ... If it is larger, then the observer can choose to maintain pointing through the gyros (drop-to-gyro) or re-acquire the guide stars (3 minute overhead per re-acquisition-note that this is not the 6-minute orbit re-acquisition) every time the telescope goes back to the target; with the first option the pointing uncertainty is about 1 milliarcsec/second due to telescope drift. ... Exposure overheads: ....