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Motor torque required to lift tiedown anchor block
jbh 4-21-99 file: torque.mcd

Work done by motor shaft = work done by jack / efficiency F L = = = is force = 120,000 lbs distance jack moves efficiency = .57 (from Nook data sheet) angle turned by motor shaft

Torque x radians = Torque x 2 revolutions = F L / L= jack travel in inches = revolutions x 1"/ (10.66 x 90) (Nook jack screw pitch is 1", jack gear ratio is 10.66:1 , Winsmith input gearbox ratio is 90:1) So Torque = F L /( 2 revolutions ) = F/( 2 10.66 90] ) = 120,000/ (2 .57 10.66 90) = 35 inch pounds = 2.9 ft lbs. The rated torque of the Kollmorgen M207-C motor is 4.75 ft lbs (continuous stall) (Current for this torque is 10A). 14.4 ft lbs (peak)